Local 7 Wiki

Section 47: Heat Traced Piping & Sweeps & Field Bends

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Formulas and Measurements

  • D. of the pipe and insulation together = 12 3/4" or 12.75" One half the total outside diameter = 63/8" or 6.375" required for the fitting.
  • Determine the number of miters Maxsize Formula: 7 X CD D = Diameter D = + 6.3745), D: 2(56 + 6.375), D = 2(62.375), D = 124.75 Maxsize = €124.75 = 11.169 x.7 = 7.81840 or 7.8 Use7.8 in the Miter Formula in place of # of Miters (only the Heel size is required) Heel = (56 + 6.375) X (1.57 7.8) = 12.55 is the # of Miters Round off to the nearest even whole number which is: 12 Insen the number 12 into the Heel and Throat measurements (56 + 6.375) x 1.57 12 = (62.375) x 1.57 12 - Heel = 97.92875 12=8160 or Throat = (56 - 6.375) X 1.57 12 = (50.375) X 1.57-:-12 - 79.08875 12=6.590 or 6 5/8"

Procedure

  1. Step 2

    Total O. D. of the pipe and insulation together = 12 3/4" or 12.75" One half the total outside diameter = 63/8" or 6.375" required for the fitting. Determine the number of miters

  2. Step 3

    Maxsize Formula: 7 X CD D = Diameter D = + 6.3745), D: 2(56 + 6.375), D = 2(62.375), D = 124.75 Maxsize = €124.75 = 11.169 x.7 = 7.81840 or 7.8 Use7.8 in the Miter Formula in place of # of Miters (only the Heel size is required) Heel = (56 + 6.375) X (1.57 7.8) = 12.55 is the # of Miters Round off to the nearest even whole number which is: 12 Insen the number 12 into the Heel and Throat measurements (56 + 6.375) x 1.57 12 = (62.375) x 1.57 12 - Heel = 97.92875 12=8160 or Throat = (56 - 6.375) X 1.57 12 = (50.375) X 1.57-:-12 - 79.08875 12=6.590 or 6 5/8"